Question

steam point and ice point of a mercury thermometer are marked as 80 and 20 what will be the temperature in centigrade mercury scale at 32

Answer 1

Since 100°C = 60°M, the C degrees are 3/5 as big as the M degrees.

so, C = 3/5 (M-20) + 0

Answer 2

40°C

Answer 3

t/100=(Lt-L0)/(L100-L0)
Lt=32
L0=20
L100=80
t/100=(32-20)/(80-20)
t=12*100/60
t=20 deg C

Answer 4

20