Asked by Chizoba
Determine the ordered pair that lies on the unit circle corresponding to csc(5π/6). Thank you.
Answers
Answered by
Reiny
The wording of your question makes no sense to me.
Do you want csc(5π/6) as found on the unit circle?
We have an ordered pair associated with (5π/6) , not csc(5π/6)
I strongly suggest you print out one of the many unit circle diagrams available.
Here is one of them
https://www.google.ca/search?q=unit+circle+trigonometry&rlz=1C5CHFA_enCA690CA690&espv=2&biw=1660&bih=856&tbm=isch&imgil=b6OyxY_TLZ5-KM%253A%253BrinOamBJgRKAGM%253Bhttp%25253A%25252F%25252Fmathematica.stackexchange.com%25252Fquestions%25252F2456%25252Fgenerate-a-unit-circle-trigonometry&source=iu&pf=m&fir=b6OyxY_TLZ5-KM%253A%252CrinOamBJgRKAGM%252C_&usg=__HP98aavLGtFPfphMrS_Wm9xhprU%3D&ved=0ahUKEwiuwt603brOAhWLWxQKHTuoDDAQyjcIKA&ei=4iatV67JJou3UbvQsoAD#imgrc=b6OyxY_TLZ5-KM%3A
All ordered pairs are of the form (cosØ, sinØ)
since sin (5π/6) = 1/2
csc (5π/6) = 2
Do you want csc(5π/6) as found on the unit circle?
We have an ordered pair associated with (5π/6) , not csc(5π/6)
I strongly suggest you print out one of the many unit circle diagrams available.
Here is one of them
https://www.google.ca/search?q=unit+circle+trigonometry&rlz=1C5CHFA_enCA690CA690&espv=2&biw=1660&bih=856&tbm=isch&imgil=b6OyxY_TLZ5-KM%253A%253BrinOamBJgRKAGM%253Bhttp%25253A%25252F%25252Fmathematica.stackexchange.com%25252Fquestions%25252F2456%25252Fgenerate-a-unit-circle-trigonometry&source=iu&pf=m&fir=b6OyxY_TLZ5-KM%253A%252CrinOamBJgRKAGM%252C_&usg=__HP98aavLGtFPfphMrS_Wm9xhprU%3D&ved=0ahUKEwiuwt603brOAhWLWxQKHTuoDDAQyjcIKA&ei=4iatV67JJou3UbvQsoAD#imgrc=b6OyxY_TLZ5-KM%3A
All ordered pairs are of the form (cosØ, sinØ)
since sin (5π/6) = 1/2
csc (5π/6) = 2
Answered by
Chizoba
This is how the question appears.
Determine the ordered pair that lies on the unit circle corresponding to t=5pi/6. I'm sorry for the confusion.
Determine the ordered pair that lies on the unit circle corresponding to t=5pi/6. I'm sorry for the confusion.
Answered by
Reiny
That's not what you had originally.
Glad you changed it, now my solution should make sense to you.
Glad you changed it, now my solution should make sense to you.
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