Asked by Yathishnv27
The weight of a pure sample of KClO3 to be decomposed in order to get 0.96 of O2.
Answers
Answered by
bobpursley
well, if you get X moles of O2, you decomposed 3x/2 moles of KClO3
.96/32-3/2*massKClO3/molmassKClO3
solve for massKClO3
.96/32-3/2*massKClO3/molmassKClO3
solve for massKClO3
Answered by
Anonymous
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