52728
= 3 x 2^3 x 13^3, and (2^3 x 13^3) is a perfect cube
so dividing 52728 by 3 would leave a quotient of 17576 which is 2^3 x 13^3 or 26^3
thus the smallest such number as a divisor is 3
and the cube root of the quotient is 26
Divide 52728 by the smallest number so that the quotient is a perfect cube. Also find the cube root of the quotient
4 answers
Divide 52728 by the smallest number so that the quotient is a perfect cube
the question is :
Divide 52728 by the smallest number so that the quotient is a perfect cube
Divide 52728 by the smallest number so that the quotient is a perfect cube
Is it correct