Asked by Thanusha
A particle executes simple harmonic motion with an amplitude 4cm. At what displacement it's energy is half kinetic energy and half potential
Answers
Answered by
bobpursley
energy is proportional to amplitude squared.
if KE is 1/2, then
.5KE/KE=(x/4cm)^2
x^2=.5*16
x=4/sqrt2
if KE is 1/2, then
.5KE/KE=(x/4cm)^2
x^2=.5*16
x=4/sqrt2
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