Question

Make x the subject of the relation:1+ax 1 -ax =p/q

Answer 1

If you mean

(1+ax)/(1-ax) = p/q
q(1+ax) = p(1-ax)
q + aqx = p - apx
aqx+apx = p-q
x(ap+aq) = p-q

x = (p-q) / a(p+q)