Asked by Anonymous
Consider the following reaction between sulfur trioxide and water:
SO3(g)+H2O(l)→H2SO4(aq) A chemist allows 61.5 g of SO3 and 11.2 g of H2O to react. When the reaction is finished, the chemist collects 51.0 g of H2SO4. Determine the percent yield for the reaction.
SO3(g)+H2O(l)→H2SO4(aq) A chemist allows 61.5 g of SO3 and 11.2 g of H2O to react. When the reaction is finished, the chemist collects 51.0 g of H2SO4. Determine the percent yield for the reaction.
Answers
Answered by
Steve
convert mass to moles and see which reagent limits the reaction.
Then compare the 51.0g yield to the theoretical yield using all available materials.
Then compare the 51.0g yield to the theoretical yield using all available materials.
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