Asked by Bob
1. The graph of the parametric equations x= 2-3t, t= -1+5t is a line. What is the slope of this line?
Please help!!!!!
Please help!!!!!
Answers
Answered by
Damon
t = -1 + 5 t ? I doubt it
then
1 = 4 t
and
t = 1/4
x = 2 - 3 (1/4)
period
then
1 = 4 t
and
t = 1/4
x = 2 - 3 (1/4)
period
Answered by
Reiny
Probably meant to type:
x= 2-3t, y= -1+5t
from x= 2-3t, -----> t = (2-x)/3
rom y= -1+5t ---> t = (y+1)/5
(2-x)/3 = (y+1)/5
3y+3 = 10 - 5x
5x + 3y = 7
slope = -5/3
x= 2-3t, y= -1+5t
from x= 2-3t, -----> t = (2-x)/3
rom y= -1+5t ---> t = (y+1)/5
(2-x)/3 = (y+1)/5
3y+3 = 10 - 5x
5x + 3y = 7
slope = -5/3
Answered by
Bob
Yeah sorry I don't know why it keeps happening.
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