Asked by Anonymous

what is the value of Kc if PbCl(s)=1.5g, [Pb2+]=1.6*10^-2 M and [Cl-] =3.2*10^-2 M at equilibrium? (The molar mass of PbCl(s) is 278 g/mol and its density is 5.85g/cm^3.)
Answered by bobpursley
Kc=[Pb2+]*[2*Cl-]^2

Kc=1.6E-2 * 4*(3.2E-2)^2
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