Asked by chichi

Rewrite the expression tan(90°−θ)sinθ as one of the six trigonometric functions of acute angle thetaθ.

Please show work + answer. I have a few of them to do. Thanks.

Answers

Answered by Scott
tan(90º - Θ) = cotan(Θ)

cotan(Θ) = cos(Θ) / sin(Θ)

[cos(Θ) / sin(Θ)] * sin(Θ) = cos(Θ)
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