Asked by amir
The numerator of a fractionis 5 less than twice the denominator. If the numerator is decreased by 1 and the denominator is increased by 3, the value of the new fraction is 5/4. Find the original fraction.
Answers
Answered by
Reiny
old denominator --- D
old numerator --- 2D-5
new denomintor D-1
new denom. 2D-5 + 3
so (D-1)/(2D-2) = 5/4
solve
old numerator --- 2D-5
new denomintor D-1
new denom. 2D-5 + 3
so (D-1)/(2D-2) = 5/4
solve
Answered by
Reiny
I seem to be making some silly copying errors tonight
change to :
new denomintor D+3
new numerator 2D-5 - 1
so (2D-6)/(D+3) = 5/4
solve
change to :
new denomintor D+3
new numerator 2D-5 - 1
so (2D-6)/(D+3) = 5/4
solve
Answered by
amir
This is my work:
D-1 5
-----= -- Cross multiply you get:
2D-2 4 10D-10=4D-4
-4D -4D
6D-10=-4
+10+10
6D=6
-----
6 6
D=1?
D-1 5
-----= -- Cross multiply you get:
2D-2 4 10D-10=4D-4
-4D -4D
6D-10=-4
+10+10
6D=6
-----
6 6
D=1?
Answered by
amir
Oh now I get it. in the last step
3D=39
-----
3 3
so D=13
tysm!
your a genius.
3D=39
-----
3 3
so D=13
tysm!
your a genius.
Answered by
jing
THE DENOMINATOR IS 4 MORE THAN ITS NUMERATOR.IT IS DECREASED FROM NUMERATOR AND 2 IS ADDED TO THE DENOMINATOR,THE RESULTING FRACTION IS 3/4.FIND THE ORIGINAL FRACTION.
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