Asked by tor
The equation
2^2x−5×2^x+6=0
has two solutions. The smaller is ? and the larger is ?.
2^2x−5×2^x+6=0
has two solutions. The smaller is ? and the larger is ?.
Answers
Answered by
Steve
this is just a quadratic in 2^x, since 2^2x = (2^x)^2
So, it factors into
(2^x-3)(2^x-2) = 0
So, 2^x = 2 or 3
That means x = 1 or log<sub>2</sub>(3)
So, it factors into
(2^x-3)(2^x-2) = 0
So, 2^x = 2 or 3
That means x = 1 or log<sub>2</sub>(3)
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