Asked by steve
a woman drives at a speed of 20m/s for part of a trip and at a speed of 30m/s for the rest of the trip if she spends 10 minutes driving at each speed determine her average speed for the full trip. If instead she drives 10 kilometers at each speed determine her average speed for the full trip.
Answers
Answered by
Scott
10 min = 600 s
600 s (20 m/s + 30 m/s) = 30 km
ave spd = 30 km / 20 min = 1.5 km/min
10 km / 20 m/s = 500 s
10 km / 30 m/s = 1000/3 s
20 km / (1500/3 s + 1000/3 s) =
... 60 / 2500 km/s = 36/25 km/min =
... 1.44 km/min
600 s (20 m/s + 30 m/s) = 30 km
ave spd = 30 km / 20 min = 1.5 km/min
10 km / 20 m/s = 500 s
10 km / 30 m/s = 1000/3 s
20 km / (1500/3 s + 1000/3 s) =
... 60 / 2500 km/s = 36/25 km/min =
... 1.44 km/min
Answered by
Henry
a. (20+30)/2 = 25 m/s. = Avg. speed.
b. 20*t1 = 10,000m., t1 = 500 s.
30*t2 = 10,000m, t2 = 333.3 s.
Total time = t1+t2 = 500 + 333.3 = 833.3 s.
Avg. speed = (d1+d2)/(t1+t2) = 20,000/833.3 = 24 m/s.
b. 20*t1 = 10,000m., t1 = 500 s.
30*t2 = 10,000m, t2 = 333.3 s.
Total time = t1+t2 = 500 + 333.3 = 833.3 s.
Avg. speed = (d1+d2)/(t1+t2) = 20,000/833.3 = 24 m/s.
Answered by
Carlos
12
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