Question
a woman drives at a speed of 20m/s for part of a trip and at a speed of 30m/s for the rest of the trip if she spends 10 minutes driving at each speed determine her average speed for the full trip. If instead she drives 10 kilometers at each speed determine her average speed for the full trip.
Answers
10 min = 600 s
600 s (20 m/s + 30 m/s) = 30 km
ave spd = 30 km / 20 min = 1.5 km/min
10 km / 20 m/s = 500 s
10 km / 30 m/s = 1000/3 s
20 km / (1500/3 s + 1000/3 s) =
... 60 / 2500 km/s = 36/25 km/min =
... 1.44 km/min
600 s (20 m/s + 30 m/s) = 30 km
ave spd = 30 km / 20 min = 1.5 km/min
10 km / 20 m/s = 500 s
10 km / 30 m/s = 1000/3 s
20 km / (1500/3 s + 1000/3 s) =
... 60 / 2500 km/s = 36/25 km/min =
... 1.44 km/min
a. (20+30)/2 = 25 m/s. = Avg. speed.
b. 20*t1 = 10,000m., t1 = 500 s.
30*t2 = 10,000m, t2 = 333.3 s.
Total time = t1+t2 = 500 + 333.3 = 833.3 s.
Avg. speed = (d1+d2)/(t1+t2) = 20,000/833.3 = 24 m/s.
b. 20*t1 = 10,000m., t1 = 500 s.
30*t2 = 10,000m, t2 = 333.3 s.
Total time = t1+t2 = 500 + 333.3 = 833.3 s.
Avg. speed = (d1+d2)/(t1+t2) = 20,000/833.3 = 24 m/s.
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