Asked by chizoba
Use identities to find the exact value of the trigonometric expression below.
1/cos2 * π/16 - 1/cot2 * π/16
PS: in words, the problem is, one divided by cosine-squared, then beside the cosine-square (still in the denominator) is pi/16. Minus one divided by cotangent-squared, then beside the cotangent-squared (still in the denominator) is pi dived by 16.) please show steps so that I can learn this.
1/cos2 * π/16 - 1/cot2 * π/16
PS: in words, the problem is, one divided by cosine-squared, then beside the cosine-square (still in the denominator) is pi/16. Minus one divided by cotangent-squared, then beside the cotangent-squared (still in the denominator) is pi dived by 16.) please show steps so that I can learn this.
Answers
Answered by
Reiny
let x = π/6 for easier typying
so your 1/cos2 * π/16 - 1/cot2 * π/16
= 1/cos^2 x - 1/cot^2 x
= sec^2 x - tan^2 x
since sec^2 x = 1 + tan^2 x ,
= 1 + tan^2 x - tan^2 x
= 1
so your 1/cos2 * π/16 - 1/cot2 * π/16
= 1/cos^2 x - 1/cot^2 x
= sec^2 x - tan^2 x
since sec^2 x = 1 + tan^2 x ,
= 1 + tan^2 x - tan^2 x
= 1
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.