Question
when solving the exponential equation, 2^2x-1=16 what do I do first? do I convert to a log equation?
Answers
bobpursley
I would take the log base 2 of each side.
Reiny
I think you mean 2^(2x-1) = 16
taking logs would be the hard way of doing it.
Notice that 16 is a power of 2, namely 16 = 2^4
so 2^(2x-1) = 2^4
clearly 2x-1 = 16
2x=17
x = 17/2
taking logs would be the hard way of doing it.
Notice that 16 is a power of 2, namely 16 = 2^4
so 2^(2x-1) = 2^4
clearly 2x-1 = 16
2x=17
x = 17/2
Reiny
<clearly 2x-1 = 16>
I meant to type
clearly 2x-1 = 4
2x=5
x=5/2
I meant to type
clearly 2x-1 = 4
2x=5
x=5/2