Asked by chizoba
Determine the missing coordinate of the point (4/7,y) that lies on the graph of the unit circle in quadrant IV. Please show the steps because I need to solve more. Thank you.
Answers
Answered by
Damon
x^2 + y^2 = 1
16/49 + y^2 = 49/49
y^2 = 33/49
y = +/- sqrt (33) /7
so since in Q IV where y is negative
(4/7, -sqrt(33)/7 )
16/49 + y^2 = 49/49
y^2 = 33/49
y = +/- sqrt (33) /7
so since in Q IV where y is negative
(4/7, -sqrt(33)/7 )
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