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the 10th term of an arithmetic sequence is equal to the sum of 40 and 5th term.If the 15th term is 127 what is its common difference?what is its first term?what is the sum of the first 30 terms.

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a+9d = 40 + a+4d
a+14d = 127

solve for a and d, then find

S30 = 30/2 (2a+29d)

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