A car takes up from west and accelerate uniformly at the rate of 4m/s square until it reaches a velocity of 10m/s. It then maintains this speed for 5secs and later decelerate at the rate of 2m/s square till it reaches its destination

Question

a) draw the velocity time graph of the motion
b) compute the time taken for the car to reach the velocity of 10m/s and the time taken decelerate
c) find the total distance covered in the course of this motion.

Answer 1

time to accelerate

10m/s / 4m/s^2 = 2.5s

deceleration takes twice as long, since the rate is half as great.

Now figure the distance using the good old formula

s = v_ot + 1/2 at^2

for each part of the trip.