Asked by aina
A 2000 kg car is traveling at 20.0 m/s. Then, it puts on the brakes and comes to a complete stop. The heat generated due to the stopping heats up the brakes. The mass of the brake system is 20.0 kg and it has a specific heat of 0.200 kcal/kg °C. What is the increase in the temperature of the brakes? ( 1 cal = 4.186 J)
Answers
Answered by
Damon
kinetic energy = (1/2) m v^2
that goes into heating the brakes
(use Joules not calories)
energy
=specific heat*mass*(Tend-Tbegin)
that goes into heating the brakes
(use Joules not calories)
energy
=specific heat*mass*(Tend-Tbegin)
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