Asked by Yug
If perimeter is 62 cm and area is 198 squared cm what are the dimensions?
Answers
Answered by
Steve
2(x+y) = 62
xy = 198
x+y=31
y = 31-x
x(31-x) = 198
x^2-31x+198 = 0
(x-9)(x-22) = 0
...
xy = 198
x+y=31
y = 31-x
x(31-x) = 198
x^2-31x+198 = 0
(x-9)(x-22) = 0
...
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