Asked by jose
The solution of x for equation
a (bx - c) = d - (x + e)
(a > 0 and b > 0)
the answer is x = ac + d - e/ab + 1
How?
a (bx - c) = d - (x + e)
(a > 0 and b > 0)
the answer is x = ac + d - e/ab + 1
How?
Answers
Answered by
bobpursley
abx-ac=d-x-e
ab=-1
which immediately poses a problem, because either a or b is negative, which is <0, and the problem stated both were >0
ab=-1
which immediately poses a problem, because either a or b is negative, which is <0, and the problem stated both were >0
Answered by
Steve
a(bx-c) = d-(x+e)
abx-ac=d-x-e
(ab+1)x = ac+d-e
x = (ac+d-e)/(ab+1)
abx-ac=d-x-e
(ab+1)x = ac+d-e
x = (ac+d-e)/(ab+1)
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