The solution of x for equation

Question

a (bx - c) = d - (x + e)
(a > 0 and b > 0)

the answer is x = ac + d - e/ab + 1

How?

Answer 1

abx-ac=d-x-e

ab=-1
which immediately poses a problem, because either a or b is negative, which is <0, and the problem stated both were >0

Answer 2

a(bx-c) = d-(x+e)
abx-ac=d-x-e
(ab+1)x = ac+d-e

x = (ac+d-e)/(ab+1)