Asked by Anna
I need to understand how to calculate the final 2 steps of this problem. Appreciate any help:
For a circuit, consisting of a single battery and two light bulbs in parallel, what is the total resistance of the circuit if each light bulb has a resistance of 6.3 ohms?
1/Rt=1/R1+1/R2 = .317 ohms
How much current is being drawn from the battery if the battery provides 1.5 Volts?
DON'T UNDERSTAND
What is the current through each bulb? DON'T UNDERSTAND
For a circuit, consisting of a single battery and two light bulbs in parallel, what is the total resistance of the circuit if each light bulb has a resistance of 6.3 ohms?
1/Rt=1/R1+1/R2 = .317 ohms
How much current is being drawn from the battery if the battery provides 1.5 Volts?
DON'T UNDERSTAND
What is the current through each bulb? DON'T UNDERSTAND
Answers
Answered by
Steve
each bulb is a separate branch of the circuit, and so has the same voltage drop.
Since they have the same resistance, each bulb gets a current of 1.5V/6.3Ω = 0.238A
Note that 1/Rt = 0.317, so Rt = 3.15 = 6.3/2 Ω
Since they have the same resistance, each bulb gets a current of 1.5V/6.3Ω = 0.238A
Note that 1/Rt = 0.317, so Rt = 3.15 = 6.3/2 Ω
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