An infinitely-long wire with resistivity 2.0*10^-8 ohm*m initially has 1.5 A of "conduction" current flowing through it. When the emf connected to the wire is turned off, this current stops in time of .6ns. Estimate the amount of displacement current created in the wire as the conduction current stops. Assume the dielectric constant of the wire is equal to one. Also, how would the magnitude of the magnetic field created by the displacement current compare to the field created by the conduction? Explain.

Question

An infinitely-long wire with resistivity 2.0*10^-8 ohm*m initially has 1.5 A of "conduction" current flowing through it. When the emf connected to the wire is turned off, this current stops in time of .6ns. Estimate the amount of displacement current created in the wire as the conduction current stops. Assume the dielectric constant of the wire is equal to one. Also, how would the magnitude of the magnetic field created by the displacement current compare to the field created by the conduction? Explain.
So for the first question I did 1.5A=1*(8.85*106-12 C^2/(N*m^2))*(BAcos(theta)/(6*10^-10s) and came up with 101.69=BAcos(theta), but I know this isn't right. What did I do wrong? For the second question I think you use the formula E0*(dE/dt), how di I know what dE is?