draw your triangle.
secθ = r/x and x<0, so θ is in QII or QIII
x = -3
r = √20
y = ±√11
Now just recall that tanθ = y/x, so it will be ±√11/3, depending on the quadrant.
if sec(x) = - squaroot 20 /3
(squroot applies to 20 not the fraction)
then state the exact vale of tan (x)
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