Asked by Alissa
                c and d are positive consecutive odd integers whose sum is 240. If c > d, then 1/square root of c=? Help?
            
            
        Answers
                    Answered by
            Bosnian
            
    c and d are positive consecutive odd integers mean :
c = d + 2 becouse :
if d are odd integers, next integer are d + 2
So:
c + d = 240
d + d + 2 = 240
2 d + 2 = 240 Subtract 2 to both sides
2 d + 2 - 2 = 240 - 2
2 d = 238 Divide both sides by2
d = 238 / 2 = 119
c = d + 2
c = 119 + 2
c = 121
1/square root of c = 1 / square root of 121 = 1 / 11
    
c = d + 2 becouse :
if d are odd integers, next integer are d + 2
So:
c + d = 240
d + d + 2 = 240
2 d + 2 = 240 Subtract 2 to both sides
2 d + 2 - 2 = 240 - 2
2 d = 238 Divide both sides by2
d = 238 / 2 = 119
c = d + 2
c = 119 + 2
c = 121
1/square root of c = 1 / square root of 121 = 1 / 11
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