A room is 8m×6m.how many tiles of 8cm×10cm are required to cover the floor?

Answer 1

The room is 800 cm by 600 cm, and the tile is 8 cm by 10 cm, so the tiles will fit exactly along either side. (ignoring any grouting gaps)

area of floor = 480,000 cm^2
area of one tile = 80 cm^2
number of tiles = 480,000/80 or 6000 tiles

or
tiles along the length = 800/8 = 100 tiles
tiles along the width = 600/10 = 60 tiles
number of tiles = 100(60) = 6000

or
area of floor = 8(6) or 48 m^2
area of one tile = .08(.10) or .006 m^2
number of tiles = 48/.006 or 6000 tiles

Answer 2

Area of the room=8m×6m
=48m²=48×10⁴cm
Area of tiles =8×10=80cm
No.of tiles=480000/80
=6000