Asked by Rayan
an empty rd bottle weighs 60 grams but weighs 120 gram when completely filled with water when the bottle is completely with an unknown liquid it weighs 90 gram what will be the volume of the rd bottle
Answers
Answered by
Steve
just figure the mass of water, and recall that water has a density of 1g/cm^3
No idea what the unknown liquid has to do with anything.
No idea what the unknown liquid has to do with anything.
Answered by
Mohini
Mass of empty RD bottle (m1)=60 g Filled with liquid (m2)= 120g
Filled with unkoen liquid (m3)=90g
Mass of water = m2 - m1= 120g-60g
60g
Density =mass /volume
Volume = mass /density
= 60g *1 g / cm-3
= 60cm-3
Volume of water = volume of RD bottle
Filled with unkoen liquid (m3)=90g
Mass of water = m2 - m1= 120g-60g
60g
Density =mass /volume
Volume = mass /density
= 60g *1 g / cm-3
= 60cm-3
Volume of water = volume of RD bottle
Answered by
ashriel
please work it out for me
Answered by
Hero
very easy
Answered by
Hello
Solution-
To find the volume of RD bottle,
Mass of empty RD bottle (m1) = 60 g
Mass of RD bottle + water (m2) = 120 g
Now,
Mass of water = m2 -m1
= (120 - 60) g
= 60 g
As the density of water is 1g/cc so the volume of water in the bottle is 60 cc. This means the volume of the RD bottle is 60 cc.
Ans. The volume of the RD bottle is 60 cc.
To find the volume of RD bottle,
Mass of empty RD bottle (m1) = 60 g
Mass of RD bottle + water (m2) = 120 g
Now,
Mass of water = m2 -m1
= (120 - 60) g
= 60 g
As the density of water is 1g/cc so the volume of water in the bottle is 60 cc. This means the volume of the RD bottle is 60 cc.
Ans. The volume of the RD bottle is 60 cc.
Answered by
Anonymous
M^1= 60 gm
M^2=120 gm
Mass = M^2 - M^1
= 60 gm
Density= 1g/cc
Volume= 60 gm/1g.cc
= 60 cc ( ANSWER )
M^2=120 gm
Mass = M^2 - M^1
= 60 gm
Density= 1g/cc
Volume= 60 gm/1g.cc
= 60 cc ( ANSWER )
Answered by
Ishika chamoli
It's correct
Answered by
manya gupta
very poor app.... brainly and toppr is just the best
Answered by
om
poor app
Answered by
om
poor app and one thing more Mohini your unknown spelling is wrong.
Answered by
Ishika paul
Not so good 👍👍👍👍👍👍👍
Answered by
Anonymous
Very poor app
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