If the point (40,3) is on the graph of y=f(x), what point must be on the graph of y=8f(8x) (5,24)
just solve
x+13 = -12
x = -25
y = -(-8/4-13) = 15
So, the new graph must contain (-25,15)
similarly for the other one.
The graph of y=v(x) contains the point (−12,−8). What point must be on the graph of each of the functions below?
Enter points as (a,b) including the parentheses.
The graph of y=−(v(1/4(x+13))−13) must contain the point (?,?)
The graph of y=4v(−3x−13)−9 must contain the point (?,?)
3 answers
for the first i got (?,21)
for the second (?,-41)
im stuck
for the second (?,-41)
im stuck
ok got it thx!