Asked by Nicole

A machine starts dumping sand at the rate of 20 m3/min, forming a pile in the shape of a cone. The height of the pile is always twice the length of the base diameter. After 5 minutes, how fast is the base area of the base increasing?

I honestly have no idea how to start this question

Answers

Answered by Reiny
Since the height is twice the diameter, the height is equal to the radius of the circular base.
Let the radius be r
V = (1/3)π r^2 h, but h = r
V = (1/3) π r^3
dV/dt = π r^2 dr/dt
dr/dt = 20/(πr^2) **

when t = 5 min, V = 5(20) = 100 m^3
100 = (1/3)πr^3
300 = πr^3
r^3 = 300/π
r = (300/π)^(1/3) ***

area of base = A = πr^2
dA/dt = 2π r dr/dt
= 2π(***)(**)
= ......

I will let you do the button-pushing
Answered by Steve
huh? height is twice the diameter, not half h = 4r

Make that change, Nicole, and redo the steps.
Answered by Reiny
thanks Steve

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