hf=hi+1/2 gt^2
hf=0 hi=25 t=2.26
g=-25*2/2.26^2
hf=0 hi=25 t=2.26
g=-25*2/2.26^2
d = 1/2 * g * t^2,
where:
- d is the distance fallen,
- g is the acceleration due to gravity, and
- t is the time taken.
Given that the object falls from a height of 25 meters and takes 2.26 seconds, we can use this equation to find the acceleration due to gravity.
25 = 1/2 * g * (2.26)^2.
To solve for g, we can rearrange the equation:
g = (2 * d) / t^2.
Plugging in the values, we get:
g = (2 * 25) / (2.26)^2 ≈ 9.79 m/s^2.
So, the acceleration due to gravity is approximately 9.79 m/s^2.
Now, let's calculate how far the object fell during the first second and the second second.
During the first second (t = 1), we can use the same equation to find the distance fallen:
d1 = 1/2 * g * t^2 = 1/2 * 9.79 * 1^2 = 4.89 meters.
Therefore, during the first second, the object fell approximately 4.89 meters.
During the second second (t = 2), we can again use the same equation:
d2 = 1/2 * g * t^2 = 1/2 * 9.79 * 2^2 = 19.58 meters.
So, during the second second, the object fell approximately 19.58 meters.
To summarize:
- The acceleration due to gravity is approximately 9.79 m/s^2.
- The object fell approximately 4.89 meters during the first second.
- The object fell approximately 19.58 meters during the second second.