Question
The expenses of orphanage are party constant and partly vary as the number of the boys in the orphanage. The expenses were Rs. 10,000 for 150 boys and Rs. 8,400 for 120 boys . Find the expenses for 330 boys.
Answers
your equation takes the form
cost = nx + b, where x is the number of boys, n is the cost per boy and b is the constant
given: (150,10000) and (120,8400)
cost per boy = (10000 - 8400)/(150-120)
= 160/3
(notice this is just like finding the "slope" )
so
Cost = (160/3)x + b
use of the cases, (150,10000)
10000 = (160/3)(150) + b
b = 2000
cost = (160/3)x + 2000
when x = 330
cost = (160/3)(330) + 2000 = 19600
cost = nx + b, where x is the number of boys, n is the cost per boy and b is the constant
given: (150,10000) and (120,8400)
cost per boy = (10000 - 8400)/(150-120)
= 160/3
(notice this is just like finding the "slope" )
so
Cost = (160/3)x + b
use of the cases, (150,10000)
10000 = (160/3)(150) + b
b = 2000
cost = (160/3)x + 2000
when x = 330
cost = (160/3)(330) + 2000 = 19600
Thankyou :D
Thankyou
Why are you switching names ?
No not switching names that's my friend Sarvesh. We both study together
Can u please answer one more question of his?
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