Asked by Madhura
The expenses of orphanage are party constant and partly vary as the number of the boys in the orphanage. The expenses were Rs. 10,000 for 150 boys and Rs. 8,400 for 120 boys . Find the expenses for 330 boys.
Answers
Answered by
Reiny
your equation takes the form
cost = nx + b, where x is the number of boys, n is the cost per boy and b is the constant
given: (150,10000) and (120,8400)
cost per boy = (10000 - 8400)/(150-120)
= 160/3
(notice this is just like finding the "slope" )
so
Cost = (160/3)x + b
use of the cases, (150,10000)
10000 = (160/3)(150) + b
b = 2000
cost = (160/3)x + 2000
when x = 330
cost = (160/3)(330) + 2000 = 19600
cost = nx + b, where x is the number of boys, n is the cost per boy and b is the constant
given: (150,10000) and (120,8400)
cost per boy = (10000 - 8400)/(150-120)
= 160/3
(notice this is just like finding the "slope" )
so
Cost = (160/3)x + b
use of the cases, (150,10000)
10000 = (160/3)(150) + b
b = 2000
cost = (160/3)x + 2000
when x = 330
cost = (160/3)(330) + 2000 = 19600
Answered by
Sarvesh
Thankyou :D
Answered by
Madhura
Thankyou
Answered by
Reiny
Why are you switching names ?
Answered by
Madhura
No not switching names that's my friend Sarvesh. We both study together
Answered by
Madhura
Can u please answer one more question of his?
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