Asked by brat
Robin flies to San Francisco from LA in 4 hours. she flies back in 3 hours. if the wind is blowing from the north at velocity of 20mph during both flights, what was the airspeed of the plane (it's speed in the air)?
Answers
Answered by
Steve
since distance = speed * time
4(s-20) = 3(s+20)
and we know what airspeed: it's its speed in the air. (note apostrophe)
4(s-20) = 3(s+20)
and we know what airspeed: it's its speed in the air. (note apostrophe)
Answered by
Reiny
I think we are to assume that San Francisco is just about north of LA
airspeed of plane ---- x mph
speed from SF to LA --- x + 20
speed from LA to SF ---- x - 20
distance one way = 4(x-20)
distance the other way = 3(x+20)
same distance, so
4x - 80 = 3x + 60
x = 140
speed of plane was only 140 mph ???
check:
4(120) =480
3(160) = 480
airspeed of plane ---- x mph
speed from SF to LA --- x + 20
speed from LA to SF ---- x - 20
distance one way = 4(x-20)
distance the other way = 3(x+20)
same distance, so
4x - 80 = 3x + 60
x = 140
speed of plane was only 140 mph ???
check:
4(120) =480
3(160) = 480
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