Asked by peejhay
find the value of k so that k-3,k+1,4k-2 form a geometric sequence.
Answers
Answered by
Reiny
to form a GS, the square of the middle term must equal to product of the outer terms
(k+1)^2 = (k-3)(4k-2)
k^2 + 2k + 1 = 4k^2 - 14k + 6
3k^2 - 16k + 5 = 0
(k - 5)(3k - 1) = 0
k = 5 or k = 1/3
(k+1)^2 = (k-3)(4k-2)
k^2 + 2k + 1 = 4k^2 - 14k + 6
3k^2 - 16k + 5 = 0
(k - 5)(3k - 1) = 0
k = 5 or k = 1/3
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