Asked by daniel
A car on the bridge weighs 2oooN and is 6m away from one of the bridge piers and 4m from the other. How much force does each pier exert to support the car? Pivot point is the weight of the car on the bridge.
Answers
Answered by
Scott
combined force is 2 kN
each pier acts as a fulcrum in a class 2 lever system
6 m * 2 kn = 10 m * f1
4 m * 2 kn = 10 m * f2
each pier acts as a fulcrum in a class 2 lever system
6 m * 2 kn = 10 m * f1
4 m * 2 kn = 10 m * f2
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