How long does it take the bomb to fall 8000m? 4.9t^2 = 8000, so t=40 s
In 40s, the bomb will travel 8000m.
What a coinkidink!
So, the angle is just 45°
An aircraft flying at a horizontally height of 8000m above the ground at 200 metre per second drops a bomb on it's target on the ground. Find the angle between the vertical and the line joining the aircraft and the target immediately the bomb is released.
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