Asked by Lottie
Approximate the solutions (to three decimal places) of the given equation in
the interval
(- pi/2, pi/2)
6 sin 2x − 8 cos x + 9 sin x = 6
Can you help with this please? I am studying for my Pre Calculus 1 exam and am stuck on this question...!
The answer options are
a. x = 0.398
b. x = 0.094
c. x = 0.139
d. x = 0.730
e. x = 1.336
the interval
(- pi/2, pi/2)
6 sin 2x − 8 cos x + 9 sin x = 6
Can you help with this please? I am studying for my Pre Calculus 1 exam and am stuck on this question...!
The answer options are
a. x = 0.398
b. x = 0.094
c. x = 0.139
d. x = 0.730
e. x = 1.336
Answers
Answered by
Reiny
6 sin 2x − 8 cos x + 9 sin x = 6
12sinxcosx - 8cosx + 9sinx - 6 = 0
4cosx(3sinx - 2) + 3(3sinx - 2) = 0
(3sinx - 2)(4cosx + 3) = 0
sinx = 2/3 OR cosx = -3/4, the last one is not possible
sinx = 2/3
x = .7297..
which matches b)
Make sure your calculator is set to radians for these type of questions, unless the question specifies degrees.
12sinxcosx - 8cosx + 9sinx - 6 = 0
4cosx(3sinx - 2) + 3(3sinx - 2) = 0
(3sinx - 2)(4cosx + 3) = 0
sinx = 2/3 OR cosx = -3/4, the last one is not possible
sinx = 2/3
x = .7297..
which matches b)
Make sure your calculator is set to radians for these type of questions, unless the question specifies degrees.
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