Asked by Amber
An equation is given. (Enter your answers as a comma-separated list. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)
2 cos 2θ − 1 = 0
a). Find all solutions of the equations
answer--> θ= (π+6nπ)/6 , (5π+6nπ)/6
b). Find the solutions in then interval [0,2π).
θ=___________
2 cos 2θ − 1 = 0
a). Find all solutions of the equations
answer--> θ= (π+6nπ)/6 , (5π+6nπ)/6
b). Find the solutions in then interval [0,2π).
θ=___________
Answers
Answered by
Steve
Looks ok to me. It might be easier to read
π/6 + nπ
5π/6 + nπ
So, plug in various values of n to get all the solutions in [0,2π)
There will be four of them
π/6 + nπ
5π/6 + nπ
So, plug in various values of n to get all the solutions in [0,2π)
There will be four of them
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.