so, you got
tanθ = ±√3
cosθ = -1/2
tanθ = √3 means θ = π/3 or 4π/3
tanθ = -√3 means θ = 2π/3 or 5π/3
cosθ = -1/2 means θ = 2π/3 or 4π/3
so, that gives
nπ + π/3
nπ + 2π/3
nπ + 4π/3
nπ + 5π/3
2nπ + 2π/3
2nπ + 4π/3
That all boils down to just
nπ + 2π/3
nπ + 4π/3
Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)
(tan^2θ-9)(2cosθ+1)=0
θ=__________________
I got 2π/3+2πn, πn+1.249, 4π/3+2πn, πn-1.249
It was wrong :(
1 answer
1 answer