Question

20g of NaHCO3 Treated with 22g of HCl Producing 12g of the residue. What is the amount of co2 Formed ?

Answer 1

NaHCO3 + HCl ==> NaCl + H2O + CO2

mols NaHCO3 = grams/molar mass = 20/84 = approx 0.24.

mols CO2 formed if NaHCO3 is the limiting reagent (LR)is
0.24 mols NaHCO3 x (1 mol CO2/1 mol NaHCO3) = 0.24 mols CO2.

mols HCl = 22/35.5 = approx 0.62.
mols CO2 formed if HCl is the LR is 0.6 x (1 mol CO2/1 mol HCl) = 0.6 mols CO2.

In LR problems, the SMALLER amount is ALWAYS the correct answer; therefore, 0.24 mols CO2 will be formed.
grams CO2 = 0.24 mol CO2 x molar mass CO2 = ? g is you want grams and not mols CO2.
NOTE: I have estimated these numbers; you should redo all of the calculations to get better numbers.

Answer 2

I want it in grams

Answer 3

"I want" -- ??

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Answer 4

Note that I showed how to do it in mols AND in grams.