Asked by lara
A community park wants to place a rectangular billboard to inform guests of their new attractions. Suppose the length of the billboard to be placed is 5m longer than its width and the area is 500m2. What will be the length and the width of the billboard?
Let w be the width of the billboard
Let w be the width of the billboard
Answers
Answered by
Scott
L = w + 5
w * (w + 5) = 500
w² + 5 w - 500 = 0
factoring ... (w + 25) (w - 20) = 0
w = 20 ... L = 25
w * (w + 5) = 500
w² + 5 w - 500 = 0
factoring ... (w + 25) (w - 20) = 0
w = 20 ... L = 25
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