Question

Use the properties of logarithms to expand the expression. ln y(y+1)^5, I keep coming up with the same answer which is wrong.
y^5ln(y)+5y^4ln(y)+10y^3ln(y)+10y^2ln(y)+ln(y)

Answer 1

Yep, it is wrong.

ln y(y+1)^5
lny + 5ln(y+1). so I don't know where that is in, or has to do with this. y^5ln(y)+5y^4ln(y)+10y^3ln(y)+10y^2ln(y)+ln(y) ...

Are you treating this as (Y+1)^5 *lny ? I don't think that is what was intended, my guess the intended expansion is
ln{ y(y+1)^5} which is
lny + 5ln(y+1)

Answer 2

ln(y) + 5 ln(y+1)