The problem is solve x= sqrt10x-4-2

So it would be x=sqrt10x-6 right

then how would I solve for x

3 answers

as drwls laid out, square both sides, then solve the quadratic.
I have the answer as x=4 is that right?
The -4 - 2 on the right looks suspicious. Did you really mean to write
x = sqrt(10x-4) -2 ?

The correct answer depends upon where the parentheses go.

4 is a correct answer,if the sqrt is taken of 10x -4. There is also another root.
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