The problem is solve x= sqrt10x-4-2
So it would be x=sqrt10x-6 right
then how would I solve for x
3 answers
as drwls laid out, square both sides, then solve the quadratic.
I have the answer as x=4 is that right?
The -4 - 2 on the right looks suspicious. Did you really mean to write
x = sqrt(10x-4) -2 ?
The correct answer depends upon where the parentheses go.
4 is a correct answer,if the sqrt is taken of 10x -4. There is also another root.
x = sqrt(10x-4) -2 ?
The correct answer depends upon where the parentheses go.
4 is a correct answer,if the sqrt is taken of 10x -4. There is also another root.