Mr. Lakandula would like to increase his production of milkfish due to its high demand in the market. He is thinking of making a larger fishpond in his 8000 sq. m lot near a river. Help Mr. Lakandulaby making a sketch plan of the fishpond to be made. Out of the given sutuation and the sketch plan made, formulate as many quadratic equations then solve by factoring.

Cannot sketch here.

I dont know pls help me

Sir ramos ito pala yung pinaactivity mo sa amin

I DOT'N NO MA'

AM

I don't know the answer, please help me

Project for math

To help Mr. Lakandula make a sketch plan of his fishpond, we need to consider a few factors such as the shape and dimensions of the fishpond. The given information states that Mr. Lakandula has an 8000 sq. m lot near a river. However, we need more details to create an accurate sketch plan.

1. Shape of the Fishpond:
There are various shapes to consider for the fishpond, such as rectangular, square, circular, or irregular. Let's assume Mr. Lakandula wants to create a rectangular fishpond.

2. Dimensions of the Fishpond:
To determine the dimensions, we need more information. Let's assume Mr. Lakandula wants a rectangular fishpond with a length of 2x meters and a width of x meters.

Now, let's create a sketch plan of the fishpond based on the assumptions:

L = 2x meters
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| x |
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With this sketch plan, we can formulate quadratic equations based on the area and solve them by factoring.

Area of a Rectangle:
The area of a rectangle is given by the formula A = length * width.

1. Equation for the Area of the Fishpond:
Area = Length * Width
8000 = (2x) * x
8000 = 2x^2

This is the quadratic equation representing the area of the fishpond. To solve it by factoring, we need to rewrite it in standard quadratic form:

2x^2 - 8000 = 0

Now, to solve the equation by factoring, we can factor out the common factor of 2:

2(x^2 - 4000) = 0

Now, set each factor equal to zero:

x^2 - 4000 = 0

(x - 200)(x + 200) = 0

x - 200 = 0 or x + 200 = 0

x = 200 or x = -200

Since the width cannot be negative, the appropriate solution is x = 200.

Therefore, Mr. Lakandula should create a rectangular fishpond with a length of 2x = 2(200) = 400 meters and a width of x = 200 meters to utilize his 8000 sq. m lot effectively.