Asked by ylopez

Randy pushes a 30.0 kg box resting on a rough surface by exerting a force of 85.0 N. The box did not move. What is the coefficient of static friction between the box and the surface where it lies?
Answered by Scott
μ > 85.0 / (30.0 * 9.80)
Answered by Henry
Wb =M*g = 30 * 9.8 = 294 N. = Fn.

Fap-Fs = M*a, 85-Fs = M*0 = 0,
Fs = 85 N.

u = Fs/Fn = 85/294 = 0.289.

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