Question

What mass would you hang on the right side of the system in the figure to balance it -- that is, to make the clockwise and counterclockwise torques equal? (Let x1 = 33 cm and x2 = 12 cm.)

Answer 1

I do not know either mass or the x of the right hand side

Answer 2

Sorry! Mass of the weight on the left hand side, hanging from x1 = 50 g

Answer 3

so where is the fulcrum?

Answer 4

The center of the anvil. x1 = 33 cm to the left with a 50 g weight hanging. x2 = 12 cm to the right with a ? weight hanging.

Answer 5

lol, finally

33 * 50 = 12 x
x = 33 * 50/12

Answer 6

Thank you!