Asked by Milky
The students standing in a straight line , holding some marbles , which are in A.P. The sum of marbles of first 8 students is 128. 3 times the difference of marbles of 2nd and 5th place students is 36 , find the A.P.
Answers
Answered by
Reiny
Stated simply:
In an AP, the sum of the first 8 terms is 128
3 times the difference between the 2nd and 5th term is 36.
4(2a + 7d) = 128
2a + 7d = 32
3(a+d - a - 4d) = 36
-3d = 12
d = -4
in 2a + 7d = 32
2a - 28 = 32
2a = 60
a = 30
the AP is
30 26 22 18 14 10 ...
In an AP, the sum of the first 8 terms is 128
3 times the difference between the 2nd and 5th term is 36.
4(2a + 7d) = 128
2a + 7d = 32
3(a+d - a - 4d) = 36
-3d = 12
d = -4
in 2a + 7d = 32
2a - 28 = 32
2a = 60
a = 30
the AP is
30 26 22 18 14 10 ...
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