Asked by vivek pathak
Calculate number of electrons present in 9.5g of PO4^3-
Answers
Answered by
DrBob222
mols PO4^3- ion = grams/molar mass = 9.5/approx 95 = approx 0.1 but you need to confirm all of that.
There are 6.02E23 PO4^3- ions in 1 mol; therefore, there are 6.02E22 mols in the 9.5 g.
In 1 PO4^3- there are 31 electrons in the P atom and 4*8 = 32 electrons in the 4 O atoms. 31 + 32 = 63 total electrons in each PO4^3- ion. So in 6.02E22 ions there will be ......... electrons.
There are 6.02E23 PO4^3- ions in 1 mol; therefore, there are 6.02E22 mols in the 9.5 g.
In 1 PO4^3- there are 31 electrons in the P atom and 4*8 = 32 electrons in the 4 O atoms. 31 + 32 = 63 total electrons in each PO4^3- ion. So in 6.02E22 ions there will be ......... electrons.
Answered by
Anjali
5NA
Answered by
Shadab
5Na
Answered by
Arka
5x 6. 023E23
Answered by
Rabi
5 Na
Answered by
Roshani
5 NA
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