Asked by Jeff Kinka
A cube of aluminum 24.0 cm on each side is cooled from 128 °C to 20 °C. If the energy removed from the aluminum cube were added to a copper cube of the same size at 30 °C, what would be the final temperature of the copper cube?(ρAl = 2700 kg/m³; ρcopper = 8890 kg/m³)
Answers
Answered by
DrBob222
volume Al or Cu cube = 24 x 24 x 24 = ?cc.
mass Al = volume x density = ?
mass Cu = volume x density = ?
Look up specific heat Al
Look up specific heat Cu
Energy removed from Al + energy added to Cu = 0
[mass Al x specific heat Al x (Tfinal-Tinitial)] + [mass Cu x specific heat Cu x (Tfinal-Tinitial)] = 0
Substitute and solve for Tfinal Cu.
mass Al = volume x density = ?
mass Cu = volume x density = ?
Look up specific heat Al
Look up specific heat Cu
Energy removed from Al + energy added to Cu = 0
[mass Al x specific heat Al x (Tfinal-Tinitial)] + [mass Cu x specific heat Cu x (Tfinal-Tinitial)] = 0
Substitute and solve for Tfinal Cu.
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