Question

Please help don't understand how to solve it.

3xy-6x+2y^2
dx/dt=-6
x=2
y=-3
thank you

Answer 1

Neither do I. You haven't asked a question.

If you want dy/dt at (2,-3) then you just need to do

3y + 3x dy/dt - 6 + 4y dy/dt

but you can't evaluate anything, because you have no equation.

Why not try posting the entire question, not just part of it?

Answer 2

Assume x and y are functions of t, Evaluate dy/dt,
3xy-6x+2y^2
dx/dt=-6
x=2
y=-3

dy/dt

Answer 3

Still no good, but let's assume you have

3xy-6x+2y^2 = 0
Then
3y dx/dt + 3x dy/dt - 6 dx/dt + 4y dy/dt = 0
(3x+4y) dy/dt = (6-3y) dx/dt

dy/dt = 3(2-y)(dx/dt)/(3x+4y)
dy/dt = 3(5)(-6)/(6-12) = 15

But that's so only if my original equation is close.