Asked by Winsome
What is the final temperature when 8.0 x 105 J are added to 1.50 kg of ice at 0.0 °C?
Answers
Answered by
bobpursley
heat=mass*Lf+mass*specificheat*(tf-0)
8E5=1.5kg* 334kJ/kg + 1.5kg*4.18kJ/kg-C;* Tf
solve for Tf
8E5=1.5kg* 334kJ/kg + 1.5kg*4.18kJ/kg-C;* Tf
solve for Tf
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